JavaScript equivalent of jQuery's extend method

mbeasley picture mbeasley · Jun 25, 2012 · Viewed 50.3k times · Source

Background

I have a function that takes a config object as an argument. Within the function, I also have default object. Each of those objects contains properties that essentially work as settings for the rest of the code within the function. In order to prevent having to specify all of the settings within the config object, I use jQuery's extend method to fill in a new object, settings with any default values from the default object if they weren't specified in the config object:

var config = {key1: value1};
var default = {key1: default1, key2: default2, key 3: default 3};

var settings = $.extend(default, config);

//resulting properties of settings:
settings = {key1: value1, key2: default2, key 3: default 3};

Problem

This works great, but I'd like to reproduce this functionality without the need for jQuery. Is there an equally elegant (or close to) means to do this with plain ol' javascript?


Edit: Non-Duplicate Justification

This question is not a duplicate of the "How can I merge properties of two JavaScript objects dynamically?" question. Whereas that question simply wants to create an object that contains all of the keys and values from two separate objects - I specifically want to address how to do this in the event that both objects share some but not all keys and which object will get precedence (the default) for the resulting object in the event that there are duplicate keys. And even more specifically, I wanted to address the use of jQuery's method to achieve this and find an alternative way to do so without jQuery. While many of the answers to both questions overlap, that does not mean that the questions themselves are the same.

Answer

Ryan Lynch picture Ryan Lynch · Jun 25, 2012

To get the result in your code, you would do:

function extend(a, b){
    for(var key in b)
        if(b.hasOwnProperty(key))
            a[key] = b[key];
    return a;
}

Keep in mind that the way you used extend there will modify the default object. If you don't want that, use

$.extend({}, default, config)

A more robust solution that mimics jQuery's functionality would be as follows:

function extend(){
    for(var i=1; i<arguments.length; i++)
        for(var key in arguments[i])
            if(arguments[i].hasOwnProperty(key))
                arguments[0][key] = arguments[i][key];
    return arguments[0];
}