Server socket file transfer

Question

I have used server socket concept in java to transfer files like images and videos. But when i receive at the client side, i am customizing the file names. Can i get the original name of the file as it is?

For Example:

If the file from server end for transfer is "abc.txt", i need this same name to be reflected in the client end(without passing the name separately).

In the server end:

public class FileServer {
  public static void main (String [] args ) throws Exception {
    // create socket
    ServerSocket servsock = new ServerSocket(13267);
    while (true) {
      System.out.println("Waiting...");

      Socket sock = servsock.accept();
      System.out.println("Accepted connection : " + sock);
      OutputStream os = sock.getOutputStream();
    new FileServer().send(os);
      sock.close();
      }
    }

  public void send(OutputStream os) throws Exception{
      // sendfile
      File myFile = new File ("C:\\User\\Documents\\abc.png");
      byte [] mybytearray  = new byte [(int)myFile.length()+1];
      FileInputStream fis = new FileInputStream(myFile);
      BufferedInputStream bis = new BufferedInputStream(fis);
      bis.read(mybytearray,0,mybytearray.length);
      System.out.println("Sending...");
      os.write(mybytearray,0,mybytearray.length);
      os.flush();
  }
}

In the client end:

    public class FileClient{
  public static void main (String [] args ) throws Exception {


    long start = System.currentTimeMillis();


    // localhost for testing
    Socket sock = new Socket("127.0.0.1",13267);
    System.out.println("Connecting...");
    InputStream is = sock.getInputStream();
    // receive file
    new FileClient().receiveFile(is);
       long end = System.currentTimeMillis();
    System.out.println(end-start);

    sock.close();
  }

  public void receiveFile(InputStream is) throws Exception{
      int filesize=6022386;
      int bytesRead;
      int current = 0;
      byte [] mybytearray  = new byte [filesize];

        FileOutputStream fos = new FileOutputStream("def");
        BufferedOutputStream bos = new BufferedOutputStream(fos);
        bytesRead = is.read(mybytearray,0,mybytearray.length);
        current = bytesRead;


        do {
           bytesRead =
              is.read(mybytearray, current, (mybytearray.length-current));
           if(bytesRead >= 0) current += bytesRead;
        } while(bytesRead > -1);

        bos.write(mybytearray, 0 , current);
        bos.flush();
        bos.close();
  }
}

Answer 1

For the receiver to know the file name, either:

a) it must assume it knows the name because it asked for it,

b) the server sends the name first as part of the stream.

If you invent a way to send information without actually sending it, let me know and we can become billionaires. We can call it 'computer telepathy'.