I am using apache common httpclient 4.3.3 to make http 1.0 request. Here is how I make the request
HttpClient client = HttpClientBuilder.create().build();
HttpPost post = new HttpPost(url);
post.setProtocolVersion(new ProtocolVersion("HTTP", 1, 0));
// trying to remove default headers but it doesn't work
post.removeHeaders("User-Agent");
post.removeHeaders("Accept-Encoding");
post.removeHeaders("Connection");
post.setEntity(new ByteArrayEntity(ba) );
HttpResponse response = client.execute(post);
However, i can see that there are other headers automatically added to my request to the server like
Connection: Keep-Alive
User-Agent: Apache-HttpClient/4.3.3 (java 1.5)
Accept-Encoding: gzip,deflate
How can I tell httpclient not to include any other headers? I tried to removed those headers with post.removeHeaders(xxxx) but it doesn't work. Can you show me how?
Thanks,
If you call HttpClientBuilder.create()
, you will have a httpClientBuilder.
And httpClientBuilder has a lot config for default headers and this will be used to make intercepters( ex: RequestAcceptEncoding ).
For example, RequestAcceptEncoding, which implements HttpRequestInterceptor, makes Accept-Encoding: gzip,deflate
header when HttpProcessor.process() is invoked.
And httpProcessor.process() will be invoked just before invoking
final CloseableHttpResponse response = this.requestExecutor.execute(route, request, context, execAware);
You can see this code at org.apache.http.impl.execchain.ProtocolExec of httpclient-4.3.6 line 193.
If you want to remove Accept-Encoding: gzip,deflate
, call HttpClientBuilder.disableContentCompression()
like below.
HttpClient client = HttpClientBuilder.create().disableContentCompression().build();
In short, HttpClientBuilder has a lot of flags to disable/enable HttpRequestInterceptor. If you disable/enable those HttpRequestInterceptor, you can exclude/include default headers.
Sorry for my poor English, and hope you get what I mean.