iOS: optional code fragments for debug builds

iphone ios debugging release building
Jakob picture Jakob · Jan 31, 2012 · Viewed 13.9k times · Source

for my App I'd like to have a debug view that I want to have only in debug-builds and not in release builds. I don't want to change my code though. Thats why i am wondering if I can check some compiler flag if this is a release build and exclude some code that i only want to have for debug builds.

Answer

Dan F picture Dan F · Jan 31, 2012

In your projects build settings, look for the preprocessor defines section, in there you can define a variable in your debug build only, such as DEBUG=1, and then use this in your code:

#if DEBUG
    NSLog(@"This will only print in debug!");
#endif

Just make sure in your release configuration, that same define is set to 0 in the same location in your build settings

Related questions

Is it possible to disable the network in iOS Simulator?

I am trying to debug some inconsistent behaviour I am seeing in an application that gets its primary data from the internet. I don't see the issues in the simulator, just on the device, so I'd like to reproduce the …

Read More
Xcode Debugger: view value of variable

My code in a UITableViewController: delegate.myData = [myData objectAtIndex:indexPath.row]; How can I see the values of delegate.myData or indexPath.row in the Debugger? delegate.myData should be an array and indexPath.row an int. I can only …

Read More
Given a view, how do I get its viewController?

I have a pointer to a UIView. How do I access its UIViewController? [self superview] is another UIView, but not the UIViewController, right?

Read More