Criteria api query in Hibernate with not exist

Question

Im trying to write query, which returns me list of Drivers wich is not assigned to route.

My database a set up as following.

Route:
route_id
user_id//specified as driver

User:
user_id
role // need to select user, which is Driver role

Only route sees user(driver), user(driver) doesn`t see route.

This is my try to write such query.

public List<User> getUnsignedDrivers(){
    CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();

    CriteriaQuery<User> query = criteriaBuilder.createQuery(User.class);
    Root<User> user = query.from(User.class);
    query.select(user);

    Subquery<Route> subquery = query.subquery(Route.class);
    Root<Route> subRootEntity = subquery.from(Route.class);
    Predicate correlatePredicate = criteriaBuilder.equal(subRootEntity.get("Route_.User"), user);
    subquery.where(correlatePredicate);
    query.where(criteriaBuilder.not(criteriaBuilder.exists(subquery)));

    TypedQuery<User> typedQuery = entityManager.createQuery(query);
    return typedQuery.getResultList();
}

I`m new to jpa, so that is the problem.

To be more specific, i need to select user with role driver, which are not set to any route

My entities are set up as following:

    @Entity
public class Route {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

@OneToOne(fetch = FetchType.EAGER, cascade = {})
@JoinColumn(name = "user_id", nullable = true)
private User driver;
.....
@Entity
public class User {

public static enum Role {
    ADMIN, MANAGER, DRIVER;
}

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;

@Enumerated(EnumType.STRING)
@Column(nullable = false)
private Role role;

UPDATE: current query

CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();

    CriteriaQuery<User> query = criteriaBuilder.createQuery(User.class);
    Root<User> user = query.from(User.class);
    Predicate predicateRole = criteriaBuilder.equal(user.get("role"), User.Role.DRIVER);
    query.where(predicateRole);
    query.select(user);


    Subquery<Route> subquery = query.subquery(Route.class);
    Root<Route> subRootEntity = subquery.from(Route.class);
    Predicate correlatePredicate = criteriaBuilder.equal(subRootEntity.get("driver"), user);
    subquery.where(correlatePredicate);
    query.where(criteriaBuilder.not(criteriaBuilder.exists(subquery)));

    TypedQuery<User> typedQuery = entityManager.createQuery(query);
    return typedQuery.getResultList();

problem still exist

i get this exception:

java.lang.IllegalStateException: No explicit selection and an implicit one cold not be determined
at org.hibernate.ejb.criteria.QueryStructure.locateImplicitSelection(QueryStructure.java:296)
at org.hibernate.ejb.criteria.QueryStructure.render(QueryStructure.java:249)
at org.hibernate.ejb.criteria.CriteriaSubqueryImpl.render(CriteriaSubqueryImpl.java:282)
at org.hibernate.ejb.criteria.predicate.ExistsPredicate.render(ExistsPredicate.java:58)
at org.hibernate.ejb.criteria.QueryStructure.render(QueryStructure.java:258)
at org.hibernate.ejb.criteria.CriteriaQueryImpl.render(CriteriaQueryImpl.java:340)
at org.hibernate.ejb.criteria.CriteriaQueryCompiler.compile(CriteriaQueryCompiler.java:217)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:587)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:601)
at org.springframework.orm.jpa.SharedEntityManagerCreator$SharedEntityManagerInvocationHandler.invoke(SharedEntityManagerCreator.java:240)
at $Proxy25.createQuery(Unknown Source)

throws at this line TypedQuery<User> typedQuery = entityManager.createQuery(query);

Work around this works for me quite well. I wrote this, because i can`t use inverse relationship.

public List<User> getUnsignedDrivers(){
    CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();

    CriteriaQuery<User> query = criteriaBuilder.createQuery(User.class);
    Root<User> user = query.from(User.class);
    Predicate predicateRole = criteriaBuilder.equal(user.get("role"), User.Role.DRIVER);
    query.where(predicateRole);
    query.select(user);

    TypedQuery<User> typedQuery = entityManager.createQuery(query);
    List<User> allDrivers = typedQuery.getResultList();
    List<User> notAssignedDrivers = new ArrayList<User>();
    List<Route> haveDriverRoutes = getRouteWithNoDrives();
    for (User driver : allDrivers){
        if (!isDriverAssigned(haveDriverRoutes,driver.getId())){
            notAssignedDrivers.add(driver);
        }
    }
    return notAssignedDrivers;
}

private boolean isDriverAssigned(List<Route> haveDriverRoutes, long driverId){
    for(Route route : haveDriverRoutes){
        if (route.getDriver().getId() == driverId){
            return true;
        }
    }
    return false;
}

@SuppressWarnings("unchecked")
public List<Route> getRouteWithNoDrives() {
    Query query = entityManager.createQuery("SELECT o FROM " + type.getSimpleName() + " o WHERE o.driver != null");
    return  query.getResultList();
}

Answer 1

You are missing the inverse OneToOne relationship in User entity:

@OneToOne(mappedBy="driver")
private Route route;

See this link about how to map OneToOne relationships.

And you have an error in this part: subRootEntity.get("Route_.User"). This is not a valid syntax, and you don't have a property called User in Route entity: the property is called driver (after reading your latest edit).

You have 2 ways to get that Path expression, either using:

Path<User> path = subRootEntity.get("driver");
// in a compact way: 
Predicate correlatePredicate = criteriaBuilder.equal(subRootEntity.get("driver"), user);

or by use of Metamodel:

Path<User> path = subRootEntity.get(Route_.driver);
// in a compact way: 
Predicate correlatePredicate = criteriaBuilder.equal(subRootEntity.get(Route_.driver), user);

You seem to have mixed the two approaches. See this article for further info about the use of Metamodel.

The rest of the query looks correct.