I need to grab a data from XML-RPC web-service.
new XmlSlurper().parse("http://host/service")
works fine, but now I have a particular service that requires basic HTTP authentication.
How can I set username and password for parse()
method, or modify HTTP headers of the request?
Using http://username:password@host/service
doesn't help - I still get java.io.IOException: Server returned HTTP response code: 401 for URL
exception.
Thanks
I found this code over here which might help?
Editing this code to your situation, we get:
def addr = "http://host/service"
def authString = "username:password".getBytes().encodeBase64().toString()
def conn = addr.toURL().openConnection()
conn.setRequestProperty( "Authorization", "Basic ${authString}" )
if( conn.responseCode == 200 ) {
def feed = new XmlSlurper().parseText( conn.content.text )
// Work with the xml document
} else {
println "Something bad happened."
println "${conn.responseCode}: ${conn.responseMessage}"
}