I want to send graphql mutation request without sub section
mutation _ {
updateCurrentUser(fullName: "Syava", email: "[email protected]")
}
and I am getting
{
"errors": [
{
"message": "Field \"updateCurrentUser\" of type \"User\" must have a sub selection.",
...
}
]
}
add { id } to request works fine but I don't want
Also Schema code
const userType = new GraphQLObjectType({
name: 'User',
fields: () => ({
id: { type: new GraphQLNonNull(GraphQLString) },
fullName: { type: GraphQLString },
email: { type: GraphQLString },
}),
});
type: userType,
args: {
fullName: { type: GraphQLString },
email: { type: new GraphQLNonNull(emailType) },
password: { type: GraphQLString },
},
resolve: async (root, { fullName, email, password }, { rootValue }) => {
const user = await User.findById(rootValue.req.user.id);
...
return user;
},
You define the type of the field to be UserType. Even though it's a mutation, it still follows the same rules and behavior as a query. Because UserType is an object type, it requires nested fields.
mutation _ {
updateCurrentUser(fullName: "Syava", email: "[email protected]") {
fullName
email
}
}
// would respond with { fullName: 'Syava', email: '[email protected]' }
If you don't want the mutation to return a User, you can declare its type to GraphQLBoolean for example -- that's a scalar and doesn't have any nested fields.
{
type: GraphQLBoolean,
args: {
fullName: { type: GraphQLString },
email: { type: new GraphQLNonNull(emailType) },
password: { type: GraphQLString },
},
resolve: async (root, { fullName, email, password }, { rootValue }) => {
const user = await User.findById(rootValue.req.user.id);
user.fullName = fullName;
user.password = password; // or hashed to not store plain text passwords
return user.save(); // assuming save returns boolean; depends on the library you use
}
}