I have something like this:
gulp.task('default', ['css', 'browser-sync'] , function() {
gulp.watch(['sass/**/*.scss', 'layouts/*.css'], function() {
gulp.run('css');
});
});
but it does not work, because it watches two directories, the sass and the layouts directory for changes.
How do I make it work, so that gulp watches anything that happens inside those directories?
gulp.task('default', ['css', 'browser-sync'] , function() {
gulp.watch(['sass/**/*.scss', 'layouts/**/*.css'], ['css']);
});
sass/**/*.scss
and layouts/**/*.css
will watch every directory and subdirectory for any changes to .scss
and .css
files that change. If you want to change that to any file make the last bit *.*