Using Realloc in C

Question

Its really a post for some advice in terms of the use of realloc, more specifically, if I could make use of it to simplify my existing code. Essentially, what the below does, it dynamically allocate some memory, if i goes over 256, then the array needs to be increased in size, so I malloc a temp array, with 2x the size, memcpy etc. ( see below ).

I was just wondering if realloc could be used in the below code, to simplify it, any advice, sample code, or even hints on how to implement it is much appreciated!

Cheers.

void reverse(char *s) {
char p;

switch(toupper(s[0])) 
{
    case 'A': case 'E': case 'I': case 'O': case 'U':
        p = s[strlen(s)-1];
        while( p >= s )
            putchar( p-- );
        putchar( '\n' );
        break;
    default:
        printf("%s", s);
        break;
}
printf("\n");
    }

    int main(void) {
char c;
int buffer_size = 256;
char *buffer, *temp;
int i=0;

buffer = (char*)malloc(buffer_size);
while (c=getchar(), c!=' ' && c!='\n' && c !='\t') 
{
    buffer[i++] = c;
    if ( i >= buffer_size )
    {
        temp = (char*)malloc(buffer_size*2);
        memcpy( temp, buffer, buffer_size );
        free( buffer );
        buffer_size *= 2;
        buffer = temp;
    }
}
buffer[i] = '\0';
reverse(buffer);

return 0;

}

Answer 1

Yes is the short answer. Here's how it would look:

if ( i >= buffer_size )
{
    temp = realloc(buffer, buffer_size*2);
    if (!temp)
        reportError();
    buffer_size *= 2;
    buffer = temp;
}

Note that you still need to use a temporary pointer to hold the result of realloc(); if the allocation fails you still have the original buffer pointer to the still-valid existing buffer.