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Dividing 1/n always returns 0.0
I am trying to calculate p1=(1/1)*(1/2)*...*(1/n) but something is wrong and the printf gives me 0.000...0
#include <stdio.h>
int main(void) {
int i,num;
float p3;
do {
printf ("give number N>3 : \n" );
scanf( "%d", &num );
} …
convert int to float to hex
Using scanf, each number typed in, i would like my program to
print out two lines: for example
byte order: little-endian
> 2
2 0x00000002
2.00 0x40000000
> -2
-2 0xFFFFFFFE
-2.00 0xC0000000
I can get it to print out the 2 in hex
…
C/C++ - Convert 24-bit signed integer to float
I'm programming in C++. I need to convert a 24-bit signed integer (stored in a 3-byte array) to float (normalizing to [-1.0,1.0]).
The platform is MSVC++ on x86 (which means the input is little-endian).
I tried this:
float convert(const …