how to use the Multiply-Accumulate intrinsics provided by GCC?
float32x4_t vmlaq_f32 (float32x4_t , float32x4_t , float32x4_t);
Can anyone explain what three parameters I have to pass to this function. I mean the Source and destination registers and what the function returns?
Help!!!
Simply said the vmla instruction does the following:
struct
{
float val[4];
} float32x4_t
float32x4_t vmla (float32x4_t a, float32x4_t b, float32x4_t c)
{
float32x4 result;
for (int i=0; i<4; i++)
{
result.val[i] = b.val[i]*c.val[i]+a.val[i];
}
return result;
}
And all this compiles into a singe assembler instruction :-)
You can use this NEON-assembler intrinsic among other things in typical 4x4 matrix multiplications for 3D-graphics like this:
float32x4_t transform (float32x4_t * matrix, float32x4_t vector)
{
/* in a perfect world this code would compile into just four instructions */
float32x4_t result;
result = vml (matrix[0], vector);
result = vmla (result, matrix[1], vector);
result = vmla (result, matrix[2], vector);
result = vmla (result, matrix[3], vector);
return result;
}
This saves a couple of cycles because you don't have to add the results after multiplication. The addition is so often used that multiply-accumulates hsa become mainstream these days (even x86 has added them in some recent SSE instruction set).
Also worth mentioning: Multiply-accumulate operations like this are very common in linear algebra and DSP (digital signal processing) applications. ARM was very smart and implemented a fast-path inside the Cortex-A8 NEON-Core. This fast-path kicks in if the first argument (the accumulator) of a VMLA instruction is the result of a preceding VML or VMLA instruction. I could go into detail but in a nutshell such an instruction series runs four times faster than a VML / VADD / VML / VADD series.
Take a look at my simple matrix-multiply: I did exactly that. Due to this fast-path it will run roughly four times faster than implementation written using VML and ADD instead of VMLA.