I am developing GUI application via wxWidgets. It has 2 parts: GUI part and "Logic" part. I want to have Logic part totally independent on wxWidgets. But one component in the GUI returning wxVariant and I need to use it in the Logic part.
So I am looking for a way to "convert" wxVariant to boost::variant
wxVariant works like this:
wxVariant v("37");
int i = v.GetInteger(); //i==37
So I am thinking something like
string s = methodReturningWxVariant().GetString();
boost::variant bV(s);
//later in code e.g
bV.GetInt();
bV.GetBool();
Is it possible to use boost::Variant (or boost::Any) like this?
Answer
You can probably use boost::variant with some changes. To start with, you need to tell boost::variant which types it will be storing:
boost::variant<int, string, bool> v;
Since you probably will be using this type in a few places, you will probably want to create an alias for it. i.e.
typedef boost::variant<int, string, bool> myvar;
then you can use myvar directly:
myvar x = "hello";
myvar y = 20;
myvar z = false;
to retrieve values:
string s = boost::get<string>(x);
int i = boost::get<int>(y);
bool b = boost::get<bool>(z);
If you attempt to get a different type than is stored in the variant, it will throw an exception.
You can query the variant's type with the which() member function. It will return a 0-based index to the type the variant is currently holding.
switch (x.which()) {
case 0: // it's an int
case 1: // it's a string
case 2: // it's a bool
}