I've seen some answers to other boost::lexical_cast
questions that assert the following is possible:
bool b = boost::lexical_cast< bool >("true");
This doesn't work for me with g++ 4.4.3 boost 1.43. (Maybe it's true that it works on a platform where std::boolalpha
is set by default)
This is a nice solution to the string to bool problem but it lacks input validation that boost::lexical_cast provides.
I'm posting the answer to my own question here for others who may be looking for something like this:
struct LocaleBool {
bool data;
LocaleBool() {}
LocaleBool( bool data ) : data(data) {}
operator bool() const { return data; }
friend std::ostream & operator << ( std::ostream &out, LocaleBool b ) {
out << std::boolalpha << b.data;
return out;
}
friend std::istream & operator >> ( std::istream &in, LocaleBool &b ) {
in >> std::boolalpha >> b.data;
return in;
}
};
usage:
#include <boost/lexical_cast.hpp>
#include <iostream>
#include "LocaleBool.hpp"
int main() {
bool b = boost::lexical_cast< LocaleBool >("true");
std::cout << std::boolalpha << b << std::endl;
std::string txt = boost::lexical_cast< std::string >( LocaleBool( b ) );
std::cout << txt << std::endl;
return 0;
}