Using 'auto' type deduction - how to find out what type the compiler deduced?

Question

How can I find out what type the compiler deduced when using the auto keyword?

Example 1: Simpler

auto tickTime = 0.001;

Was this deduced as a float or a double?

Example 2: More complex (and my present headache):

typedef std::ratio<1, 1> sec;
std::chrono::duration<double, sec > timePerTick2{0.001};
 auto nextTickTime = std::chrono::high_resolution_clock::now() + timePerTick2;

What type is nextTickTime?

The problem I'm having is when I try to send nextTickTime to std::cout. I get the following error:

./main.cpp: In function ‘int main(int, char**)’:
./main.cpp:143:16: error: cannot bind ‘std::basic_ostream<char>’ lvalue to ‘std::basic_ostream<char>&&’
  std::cout << std::setprecision(12) << nextTickTime << std::endl; // time in seconds
            ^
In file included from /usr/include/c++/4.8.2/iostream:39:0,
             from ./main.cpp:10:
/usr/include/c++/4.8.2/ostream:602:5: error:   initializing argument 1 of ‘std::basic_ostream<_CharT, _Traits>& std::operator<<(std::basic_ostream<_CharT, _Traits>&&, const _Tp&) [with _CharT = char; _Traits = std::char_traits<char>; _Tp = std::chrono::time_point<std::chrono::_V2::system_clock, std::chrono::duration<double, std::ratio<1l, 1000000000l> > >]’
 operator<<(basic_ostream<_CharT, _Traits>&& __os, const _Tp& __x)

Answer 1

I like to use idea from Effective Modern C++ which uses non-implemented template; the type is output with compiler error:

 template<typename T> struct TD;

Now for auto variable var, after its definition add:

 TD<decltype(var)> td;

And watch error message for your compiler, it will contain type of var.