I've worked with linked lists before extensively in Java, but I'm very new to C++. I was using this node class that was given to me in a project just fine
class Node
{
public:
Node(int data);
int m_data;
Node *m_next;
};
but I had one question that wasn't answered very well. Why is it necessary to use
Node *m_next;
to point to the next node in the list instead of
Node m_next;
I understand that it is better to use the pointer version; I'm not going to argue facts, but I don't know why it's better. I got a not so clear answer about how the pointer is better for memory allocation, and I was wondering if anyone here could help me understand that better.
It's not just better, it's the only possible way.
If you stored a Node
object inside itself, what would sizeof(Node)
be? It would be sizeof(int) + sizeof(Node)
, which would be equal to sizeof(int) + (sizeof(int) + sizeof(Node))
, which would be equal to sizeof(int) + (sizeof(int) + (sizeof(int) + sizeof(Node)))
, etc. to infinity.
An object like that can't exist. It's impossible.