I created an armadillo c++ matrix as follows:
arma::mat A;
A.zeros(3,4);
I want to convert it to a vector of vectors defined by
std::vector< std::vector<double> > B(3, std::vector<double>(4) );
How do I set B to equal A? If there is not an easy way for a vector of vectors, what about an array of arrays, i.e., what if I defined B to be
double B[3][4];
In such cases you should use arma::conv_to
which is a totally superb feature of arma.
Note that this method will require from a source object to be able to be interpreted as a vector. That is why we need to do this iteratively for every row. Here is a conversion method:
#include <armadillo>
typedef std::vector<double> stdvec;
typedef std::vector< std::vector<double> > stdvecvec;
stdvecvec mat_to_std_vec(arma::mat &A) {
stdvecvec V(A.n_rows);
for (size_t i = 0; i < A.n_rows; ++i) {
V[i] = arma::conv_to< stdvec >::from(A.row(i));
};
return V;
}
And here is an exemplary usage:
#include <iomanip>
#include <iostream>
int main(int argc, char **argv) {
arma::mat A = arma::randu<arma::mat>(5, 5);
std::cout << A << std::endl;
stdvecvec V = mat_to_std_vec(A);
for (size_t i = 0; i < V.size(); ++i) {
for (size_t j = 0; j < V[i].size(); ++j) {
std::cout << " "
<< std::fixed << std::setprecision(4) << V[i][j];
}
std::cout << std::endl;
}
return 0;
}
std::setprecision
used to generate more readable output:
0.8402 0.1976 0.4774 0.9162 0.0163
0.3944 0.3352 0.6289 0.6357 0.2429
0.7831 0.7682 0.3648 0.7173 0.1372
0.7984 0.2778 0.5134 0.1416 0.8042
0.9116 0.5540 0.9522 0.6070 0.1567
0.8402 0.1976 0.4774 0.9162 0.0163
0.3944 0.3352 0.6289 0.6357 0.2429
0.7831 0.7682 0.3648 0.7173 0.1372
0.7984 0.2778 0.5134 0.1416 0.8042
0.9116 0.5540 0.9522 0.6070 0.1567
Have a good one!