Getting a Stream from a resource file / content

swinefeaster picture swinefeaster · Dec 13, 2012 · Viewed 15.5k times · Source

Is this the correct/only way of getting a Stream from a resource file?

    Uri uri = new Uri(fullPath);

    StorageFile storageFile = 
      await Windows.Storage.StorageFile.
        GetFileFromApplicationUriAsync(uri);

    IRandomAccessStreamWithContentType randomAccessStream = 
      await storageFile.OpenReadAsync();

    IInputStream resourceStream = (IInputStream)
      randomAccessStream.GetInputStreamAt(0);

All my other sources (http and local storage) return a Stream object, and it is painful to have to if-else code that uses one or the other.

I've also tried to just create a MemoryStream out of it, but I can't even find a way to get the bytes out... Please help.

    uint size = (uint)randomAccessStream.Size;
    IBuffer buffer = new Windows.Storage.Streams.Buffer(size);
    await randomAccessStream.ReadAsync(buffer, size, 
      InputStreamOptions.None);

    Stream stream = new MemoryStream(buffer); // error takes byte[] not IBuffer

IInputStream.ReadAsync() when reading from resource: http://msdn.microsoft.com/en-us/library/windows/apps/windows.storage.streams.iinputstream.readasync.aspx

while Stream.Read() and Stream.ReadAsync() look like this:

http://msdn.microsoft.com/en-us/library/system.io.stream.read.aspx

and

http://msdn.microsoft.com/en-us/library/hh137813.aspx

Thanks

Answer

swinefeaster picture swinefeaster · Dec 14, 2012

Ok I found it!

    StorageFile storageFile =
      await Windows.Storage.StorageFile.GetFileFromApplicationUriAsync(uri);

    var randomAccessStream = await storageFile.OpenReadAsync();
    Stream stream = randomAccessStream.AsStreamForRead();