How can I escape a double quote inside double quotes?

bash quotes
Sean Nguyen picture Sean Nguyen · Sep 30, 2010 · Viewed 400.9k times · Source

How can I escape double quotes inside a double string in Bash?

For example, in my shell script

#!/bin/bash

dbload="load data local infile \"'gfpoint.csv'\" into table $dbtable FIELDS TERMINATED BY ',' ENCLOSED BY '\"' LINES TERMINATED BY \"'\n'\" IGNORE 1 LINES"

I can't get the ENCLOSED BY '\"' with double quote to escape correctly. I can't use single quotes for my variable, because I want to use variable $dbtable.

Answer

Peter picture Peter · Sep 30, 2010

Use a backslash:

echo "\""     # Prints one " character.

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