In Bash, what are the differences between single quotes (''
) and double quotes (""
)?
Single quotes won't interpolate anything, but double quotes will. For example: variables, backticks, certain \
escapes, etc.
Example:
$ echo "$(echo "upg")"
upg
$ echo '$(echo "upg")'
$(echo "upg")
The Bash manual has this to say:
Enclosing characters in single quotes (
'
) preserves the literal value of each character within the quotes. A single quote may not occur between single quotes, even when preceded by a backslash.Enclosing characters in double quotes (
"
) preserves the literal value of all characters within the quotes, with the exception of$
,`
,\
, and, when history expansion is enabled,!
. The characters$
and`
retain their special meaning within double quotes (see Shell Expansions). The backslash retains its special meaning only when followed by one of the following characters:$
,`
,"
,\
, or newline. Within double quotes, backslashes that are followed by one of these characters are removed. Backslashes preceding characters without a special meaning are left unmodified. A double quote may be quoted within double quotes by preceding it with a backslash. If enabled, history expansion will be performed unless an!
appearing in double quotes is escaped using a backslash. The backslash preceding the!
is not removed.The special parameters
*
and@
have special meaning when in double quotes (see Shell Parameter Expansion).