If I run this code in bash:
echo dog dog dos | sed -r 's:dog:log:'
it gives output:
log dog dos
How can I make it replace all occurrences of dog?
You should add the g
modifier so that sed performs a global substitution of the contents of the pattern buffer:
echo dog dog dos | sed -e 's:dog:log:g'
For a fantastic documentation on sed, check http://www.grymoire.com/Unix/Sed.html. This global flag is explained here: http://www.grymoire.com/Unix/Sed.html#uh-6
The official documentation for GNU sed
is available at http://www.gnu.org/software/sed/manual/