How to use "Share image using" sharing Intent to share images in android?

Question

I have image galley app in that app I placed all the images into the drawable-hdpi folder. and i called images in my activity like this :

private Integer[] imageIDs = {
        R.drawable.wall1, R.drawable.wall2,
        R.drawable.wall3, R.drawable.wall4,
        R.drawable.wall5, R.drawable.wall6,
        R.drawable.wall7, R.drawable.wall8,
        R.drawable.wall9, R.drawable.wall10
};

So now i want know how do i share this images using sharing Intent i putted sharing code like this :

     Button shareButton = (Button) findViewById(R.id.share_button);
     shareButton.setOnClickListener(new View.OnClickListener() {
     public void onClick(View v) {
       
        Intent sharingIntent = new Intent(Intent.ACTION_SEND);
        Uri screenshotUri = Uri.parse(Images.Media.EXTERNAL_CONTENT_URI + "/" + imageIDs);

        sharingIntent.setType("image/jpeg");
        sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
        startActivity(Intent.createChooser(sharingIntent, "Share image using"));  
    
         }
    });

And i have sharing button also when i click on share button Sharing box is opening But when i cliked any service mostly its crashing or some services say : unable to open image So how i can fix this or is there any othere format code to share images ????

Edit :

I tried using the code below. But its not working.

Button shareButton = (Button) findViewById(R.id.share_button);
     shareButton.setOnClickListener(new View.OnClickListener() {
     public void onClick(View v) {

        Intent sharingIntent = new Intent(Intent.ACTION_SEND);
        Uri screenshotUri = Uri.parse("android.resource://com.android.test/*");
        try {
            InputStream stream = getContentResolver().openInputStream(screenshotUri);
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        sharingIntent.setType("image/jpeg");
        sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
        startActivity(Intent.createChooser(sharingIntent, "Share image using"));  

         }
    });

If don't mind somebody plz correct my above code OR give me a proper example plz How do i Share my images from drawable-hdpi folder

Answer 1

Bitmap icon = mBitmap;
Intent share = new Intent(Intent.ACTION_SEND);
share.setType("image/jpeg");
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
icon.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
File f = new File(Environment.getExternalStorageDirectory() + File.separator + "temporary_file.jpg");
try {
    f.createNewFile();
    FileOutputStream fo = new FileOutputStream(f);
    fo.write(bytes.toByteArray());
} catch (IOException e) {                       
        e.printStackTrace();
}
share.putExtra(Intent.EXTRA_STREAM, Uri.parse("file:///sdcard/temporary_file.jpg"));
startActivity(Intent.createChooser(share, "Share Image"));