$FreeUploadServer = Invoke-RestMethod -Uri "http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=nextuploadserver"
Invoke-RestMethod -Uri "http://rs$FreeUploadServer.rapidshare.com/cgi-bin/rsapi.cgi?sub=upload&login=43533592&password=password&filecontent=C:\libs\test.txt"
I have no clue why that isnt working, its something to do with the filecontent parameter but i have read the entire documentation about the API and i cant figure it out.
Make sure you use the -Method Post
parameter/arg combo on the second Invoke-RestMethod call. Also, take a look at this SO response to a similar question about using CURL. After looking at the question and answer, it appears that RapidShare requires filling in POST form fields. In this case you need to specify the -Body
parameter. I think you'll use a PowerShell hashtable where each entry corresponds to a form field name/value pair. Looks like the one field needed is the filecontent
field. Presumably the value is the file's contents.
Also, when you use POST, you'll have to convert the GET
query parameters to POST
form fields e.g.:
$url = "http://rs$FreeUploadServer.rapidshare.com/cgi-bin/rsapi.cgi"
$fields = @{sub='upload';login='43533592';password='password';filename='test.txt';
filecontent=([IO.File]::ReadAllText('c:\libs\test.txt'))}
Invoke-RestMethod -Uri $url -Body $fields -Method Post
If [IO.File]::ReadAlltext()
doesn't cut it perhaps try [IO.File]::ReadAllBytes()
instead.