Get first child node in XSLT using local-name()

Question

Assume we have this simple xml ...

 <books>   
    <book>
       <author/>
       <title/>
    </book>
    <book>
       <author/>
       <title/>
    </book>
 </books>

I'm using this xpath to get the elements of the first book instance.

//books[1]/*

Returns

<author/>
<title/>

And that works fine, but I have to get it working using local-name(). I've tried the following but none of these work...

//*[local-name()='books']/*

this returns repeating author and title elements, not good, I only need them from the first child

//*[local-name()='books'][0]/*

this does not return anything

Basically, I want to create a CSV file, so the first line in the output will be a header listing the book attribute names followed by the arbitrary data values. I only need to get the header part working.

author,title
john,The End is Near
sally,Looking for Answers

Answer 1

This is a FAQ -- the XPath [] operator has higher precedence (priority) than the // pseudo-operator.

So:

//someElemName[1]

selects every element named someElemName that is the first child of its parent -- and, depending on the XML document, there can be more than one such elements.

To change this, one must use brackets.

Use:

(//*[local-name() = 'book'])[1]/*

Also note: In XPath positions are 1-based, not 0-based.

XSLT-based verification:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="/">
  <xsl:copy-of select=
  "(//*[local-name() = 'book'])[1]/*"/>
 </xsl:template>
</xsl:stylesheet>

when this transformation is applied on the following XML document:

<books>
    <book num="1">
        <author num="1"/>
        <title num="1"/>
    </book>
    <book num="2">
        <author num="2"/>
        <title num="2"/>
    </book>
</books>

the wanted nodes are selected and copied to the output:

<author num="1"/>
<title num="1"/>