xargs is a command on Unix and most Unix-like operating systems used to build and execute command lines from standard input.
I want to get the number of lines in my application. I am using this code: find . "(" -name "*.m" -or …
macos xargsI want the following behavior without having to explicitly specify it with options: xargs -d '\n' Unlike with most …
command-line whitespace xargsI want to pass all the files as a single argument on Linux but I am not able to do …
linux xargsI'm pretty much confused on this. Need some clarifications. Example 1 : pgrep string | xargs ps Example 2 : find . | xargs grep whatever From …
unix xargsConsider having the results from the pipe: find . Now I would like to access in the second command behind the …
bash pipe xargsI have the following I want to do: find . -maxdepth 6 \( -name \*.tar.gz -o -name bediskmodel -o -name src -o …
find tar xargshere is my problem in short $ echo 'for i in $@; do echo arg: $i; done; echo DONE' > /tmp/test.…
shell unix xargs