Dynamically changing the start up location of a WPF window

wpf window wpf-positioning
Evan picture Evan · Oct 9, 2009 · Viewed 12.9k times · Source

This is a follow up question to an answered question [here][1].

There the startup position of a WPF window was defined in XAML. Now I'm wondering how to change those properties in code? For example could I say something like:

Window1.Top = 40 in the window load event handler? Or which window event would I need to set those for it dynamically alter the starting position?

The goal is to set the windows start position dynamically before it is rendered.

Answer

Reed Copsey picture Reed Copsey · Oct 9, 2009

This is fairly easy to do in code:

public partial class Window1 {

    public Window1()
    {
         InitializeComponent();
         this.Height = 500;
         this.Width = 500;
         this.WindowStartupLocation = WindowStartupLocation.Manual;
         this.Left = 0;
         this.Top = 0;
    }
}

You can set any of the parameters you wish, but if you're going to set Top/Left, make sure to set WindowStatupLocation (or have it set to manual in XAML).

Related questions

Changing the start up location of a WPF window

I'd like to have a WPF window open in the top right part of the screen. Right now I can achieve that by opening the window and then moving it (via movewindow in user32.dll). However, this approach means the …

Read More
How to create a WPF Window without a border that can be resized via a grip only?

If you set ResizeMode="CanResizeWithGrip" on a WPF Window then a resize grip is shown in the lower right corner, as below: If you set WindowStyle="None" as well the title bar disappears but the grey bevelled edge remains until …

Read More
Finding the handle to a WPF window

Windows forms had a property win1.Handle which, if I recall, returns the handle of the main window handle? Is there an equivalent way to get the handle of a WPF Window? I found the following code online, IntPtr windowHandle = …

Read More