Why are my set commands resulting in nothing getting stored?

gregturn picture gregturn · Jan 15, 2013 · Viewed 24.8k times · Source

I am trying to access the value of TOMCAT_VER later on, but it appears as an empty string.

if exist "%_REALPATH%\tomcat-%TOMCAT_VER2%" (
  set CATALINA_HOME=%_REALPATH%\tomcat-%TOMCAT_VER2%
  set TOMCAT_VER=%TOMCAT_VER2%
  echo "%TOMCAT_VER%"
) else if exist "%TOMCAT_VER2%" (
  set CATALINA_HOME="%TOMCAT_VER2%"
  set TOMCAT_VER="%TOMCAT_VER2%"
  echo "%TOMCAT_VER%"
)

To further debug, I inserted an echo statement right below where it gets set, but it doesn't seem to work. With echo off disabled, I can see the statement showing these variables getting set, and yet I can't seem to print them out.

Answer

jeb picture jeb · Jan 15, 2013

You found the bbb (batch beginner bug), but not the variable is empty, it's the expansion that doesn't work as expected.

Percent expansion is done when a line or a complete parenthesis block is parsed, before the code will be executed.
But to solve this you can use the delayed expansion, this doesn't expand at parse time, it expands just at execution time.

EnableDelayedExpansion adds an additional syntax to expand variables: !var!.
The percent expansion %var% is still availabe and isn't changed by the delayed expansion.
The delayed expansion of !var! is done when the expression is executed, in spite of %var%, that will be expanded in the moment of parsing (complete code blocks), before any of the commands in the blocks are executed.

setlocal EnableDelayedExpansion

if exist "!_REALPATH!\tomcat-!TOMCAT_VER2!" (
  set "CATALINA_HOME=!_REALPATH!\tomcat-!TOMCAT_VER2!"
  set "TOMCAT_VER=!TOMCAT_VER2!"
  echo !TOMCAT_VER!
) else if exist "!TOMCAT_VER2!" (
  set "CATALINA_HOME=!TOMCAT_VER2!"
  set "TOMCAT_VER=!TOMCAT_VER2!"
  echo !TOMCAT_VER!
)