How to get the fully qualified path for a file in VBScript?
I am using the Shell.Application object, which allows me to script creation of a zip file.
But in order for this to work, I need to full path of the zip file. File.zip doesn't work. I need c:\the\full\path\file.zip, even if the script is running within the same directory where the file is found.
How can I get the full path of a file in VBScript?
Something like the %~fI expansion in the cmd.exe shell.
Answer
On Scripting.FileSystemObject, there's a method called GetAbsolutePathName that does this.
This is what worked for me:
Dim folderName
folderName = "..\.."
Dim fso
Set fso = CreateObject("Scripting.FileSystemObject")
Dim fullpath
fullpath = fso.GetAbsolutePathName(folderName)
WScript.Echo "folder spec: " & folderName
WScript.Echo "fullpath: " & fullpath