Looping through all rows in a table column, Excel-VBA

Question

I'm currently working on a data set which is formatted as a table, with headers. What I need to do is cycle through all cells in a specific column and change the contents. Through research on MSDN I came up with the following for loop

for i = 1 to NumRows
    Cells(i,23).Value = "PHEV"
next i

So this would change all the cells in column 23 to read "PHEV". However, I do not build the table I'm working with myself, so I can't guarantee that the column I'm interested in will be column 23.

I'd like to implement something similar to the following:

for i = 1 to NumRows
    Cells(i,[@[columnHeader]]).Value = "PHEV"
next i

Of course, I know that that syntax is incorrect, but hopefully it sufficiently illustrates my goal.

Answer 1

If this is in fact a ListObject table (Insert Table from the ribbon) then you can use the table's .DataBodyRange object to get the number of rows and columns. This ignores the header row.

Sub TableTest()

Dim tbl As ListObject
Dim tRows As Long
Dim tCols As Long

Set tbl = ActiveSheet.ListObjects("Table1")  '## modify to your table name.

With tbl.DataBodyRange
    tRows = .Rows.Count
    tCols = .Columns.Count
End With

MsgBox tbl.Name & " contains " & tRows & " rows and " & tCols & " columns.", vbInformation

End Sub

If you need to use the header row, instead of using tbl.DataBodyRange just use tbl.Range.