If I want to cut a list of text using a string as a delimiter, is that possible? For example I have a directory where a list of shell scripts call same perl script say
abc.pl
So when I do
$grep abc.pl *
in that directory, it gives me following results
xyz.sh: abc.pl 1 2
xyz2.sh: abc.pl 2
mno.sh: abc.pl 3
pqr.sh: abc.pl 4 5
I basically want all the output after "abc.pl" (to check what range arguments are being passed to the perl right now)
When I tried
$grep abc.pl * | cut -d'abc.pl' -f2
OR
$grep abc.pl * | cut -d'abc\.pl' -f2
its giving me
cut: invalid delimiter
When I read man for cut it states
delim can be a multi-byte character.
What am I doing/interpreting wrong here?
Try using this.
$grep abc.pl * | awk -F 'abc.pl' '{print $2}'
-F fs --field-separator fs Use fs for the input field separator (the value of the FS predefined variable).