represent negative number with 2' complement technique?
I am using 2' complement to represent a negative number in binary form
Case 1:number -5
According to the 2' complement technique:
Convert 5 to the binary form:
00000101, then flip the bits
11111010, then add 1
00000001
=> result: 11111011
To make sure this is correct, I re-calculate to decimal:
-128 + 64 + 32 + 16 + 8 + 2 + 1 = -5
Case 2: number -240
The same steps are taken:
11110000
00001111
00000001
00010000 => recalculate this I got 16, not -240
I am misunderstanding something?
Answer
The problem is that you are trying to represent 240 with only 8 bits. The range of an 8 bit signed number is -128 to 127.
If you instead represent it with 9 bits, you'll see you get the correct answer:
011110000 (240)
100001111 (flip the signs)
+
000000001 (1)
=
100010000
=
-256 + 16 = -240