I'm using symfony2 and SonataAdminBundle. I have a simple Entity called Post in which I have content field that is basically html text (from a ckeditor for the record). I need to display in the Post list the content field as raw html, without escaping it. Hacking base_list_field template like this
{% block field %}{{ value|raw }}{% endblock %}
works, but it's clearly not the proper way. Any hints?
edit: SOLVED! I've defined a custom html type in the config.yml for sonata_doctrine_orm_admin:
sonata_doctrine_orm_admin:
templates:
types:
list:
html: MyBundle:Default:list_html.html.twig
And created the custom list_html.html.twig template in which i do not escape HTML:
{% extends 'SonataAdminBundle:CRUD:base_list_field.html.twig' %}
{% block field%}
{{value|raw}}
{% endblock %}
Now in the PostAdmin I can define the behaviour of the field in the configureListFields method:
$listMapper
->add('content', 'html')
The solution:
I've defined a custom html type in the config.yml for sonata_doctrine_orm_admin:
sonata_doctrine_orm_admin:
templates:
types:
list:
html: MyBundle:Default:list_html.html.twig
And created the custom list_html.html.twig template in which i do not escape HTML:
{% extends 'SonataAdminBundle:CRUD:base_list_field.html.twig' %}
{% block field%}
{{value|raw}}
{% endblock %}
Now in the PostAdmin I can define the behaviour of the field in the configureListFields method:
$listMapper
->add('content', 'html')