Most efficient way to remove leading zeros from Swift 3 string

swift3 substring leading-zero
Jazzmine picture Jazzmine · Nov 6, 2017 · Viewed 8.4k times · Source

I have a string such as "00123456" that I would like to have in an string "123456", with the leading zeros removed.

I've found several examples for Objective-C but not sure best way to do so with Swift 3.

Thanks

Answer

vadian picture vadian · Aug 7, 2018

You can do that with Regular Expression

let string = "00123456"
let trimmedString = string.replacingOccurrences(of: "^0+", with: "", options: .regularExpression)

The benefit is no double conversion and no force unwrapping.

Related questions

How to create dispatch queue in Swift 3

In Swift 2, I was able to create queue with the following code: let concurrentQueue = dispatch_queue_create("com.swift3.imageQueue", DISPATCH_QUEUE_CONCURRENT) But this doesn't compile in Swift 3. What is the preferred way to write this in Swift 3?

Read More
How to program a delay in Swift 3

In earlier versions of Swift, one could create a delay with the following code: let time = dispatch_time(dispatch_time_t(DISPATCH_TIME_NOW), 4 * Int64(NSEC_PER_SEC)) dispatch_after(time, dispatch_get_main_queue()) { //put your code which should …

Read More
How do I dispatch_sync, dispatch_async, dispatch_after, etc in Swift 3, Swift 4, and beyond?

I have lots of code in Swift 2.x (or even 1.x) projects that looks like this: // Move to a background thread to do some long running work dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0)) { let image = self.…

Read More