DispatchSourceTimer and Swift 3.0

Derreck picture Derreck · Sep 19, 2016 · Viewed 18.3k times · Source

I can't figure out how to make dispatch timer work repeatedly in Swift 3.0. My code:

let queue = DispatchQueue(label: "com.firm.app.timer",
                          attributes: DispatchQueue.Attributes.concurrent)
let timer = DispatchSource.makeTimerSource(flags: DispatchSource.TimerFlags(rawValue: UInt(0)),
                                           queue: queue)

timer.scheduleRepeating(deadline: DispatchTime.now(),
                        interval: .seconds(5),
                        leeway: .seconds(1)
)

timer.setEventHandler(handler: {
     //a bunch of code here
})

timer.resume()

Timer just fires one time and doesn't repeat itself like it should be. How can I fix this?

Answer

Rob picture Rob · Sep 19, 2016

Make sure the timer doesn't fall out of scope. Unlike Timer (where the RunLoop on which you schedule it keeps the strong reference until the Timer is invalidated), you need to maintain your own strong reference to your GCD timers, e.g.:

var timer: DispatchSourceTimer?

private func startTimer() {
    let queue = DispatchQueue(label: "com.firm.app.timer", attributes: .concurrent)

    timer?.cancel()        // cancel previous timer if any

    timer = DispatchSource.makeTimerSource(queue: queue)

    timer?.schedule(deadline: .now(), repeating: .seconds(5), leeway: .milliseconds(100))

    // or, in Swift 3:
    //
    // timer?.scheduleRepeating(deadline: .now(), interval: .seconds(5), leeway: .seconds(1))

    timer?.setEventHandler { [weak self] in // `[weak self]` only needed if you reference `self` in this closure and you want to prevent strong reference cycle
        print(Date())
    }

    timer?.resume()
}

private func stopTimer() {
    timer?.cancel()
    timer = nil
}