Swift: How to get everything after a certain set of characters

Question

Given the following string:

var snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: [phone]"

How can I extract everything that comes after "Phone:"

So in this case I want

phone = 123.456.7891

I've tried this:

    if let range = snippet.rangeOfString("Phone:") {

        let phone = snippet.substringToIndex(range.startIndex)
        print(phone) // prints 1111 West Main Street Beverly Hills, CA 90210
    }

But this prints everything BEFORE, I need everything AFTER.

Answer 1

In Swift 4, use upperBound and subscript operators and open range:

let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: [phone]"

if let range = snippet.range(of: "Phone: ") {
    let phone = snippet[range.upperBound...]
    print(phone) // prints "123.456.7891"
}

Or consider trimming the whitespace:

if let range = snippet.range(of: "Phone:") {
    let phone = snippet[range.upperBound...].trimmingCharacters(in: .whitespaces)
    print(phone) // prints "123.456.7891"
}

---

By the way, if you're trying to grab both at the same time, a regular expression can do that:

let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: [phone]"
let regex = try! NSRegularExpression(pattern: #"^(.*?)\s*Phone:\s*(.*)$"#, options: .caseInsensitive)
if let match = regex.firstMatch(in: snippet, range: NSRange(snippet.startIndex..., in: snippet)) {
    let address = snippet[Range(match.range(at: 1), in: snippet)!]
    let phone = snippet[Range(match.range(at: 2), in: snippet)!]
}

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For prior versions of Swift, see previous revision of this answer.