Check if a string exists in an array case insensitively

swift contains
Kashif picture Kashif · Jul 10, 2015 · Viewed 31k times · Source

Declaration:

let listArray = ["kashif"]
let word = "kashif"

then this 

contains(listArray, word)

Returns true but if declaration is:

let word = "Kashif"

then it returns false because comparison is case sensitive.

How to make this comparison case insensitive?

Answer

Leo Dabus picture Leo Dabus · Jul 10, 2015

Xcode 8 • Swift 3 or later

let list = ["kashif"]
let word = "Kashif"

if list.contains(where: {$0.caseInsensitiveCompare(word) == .orderedSame}) {
    print(true)  // true
}

alternatively:

if list.contains(where: {$0.compare(word, options: .caseInsensitive) == .orderedSame}) {
    print(true)  // true
}

if you would like to know the position(s) of the element in the array (it might find more than one element that matches the predicate):

let indices = list.indices.filter { list[$0].caseInsensitiveCompare(word) == .orderedSame }
print(indices)  // [0]

Related questions

how to check if a property value exists in array of objects in swift

I am trying to check if a specific item (value of a property) exists in a array of objects, but could not find out any solution. Please let me know, what i am missing here. class Name { var id : Int …

Read More
How to check if a string contains an int? -Swift

I need to know if a string contains an Int to be sure that a name the user entered is a valid full name, for that I need to either make the user type only chars, or valid that there …

Read More
How to change Status Bar text color in iOS

My application has a dark background, but in iOS 7 the status bar became transparent. So I can't see anything there, only the green battery indicator in the corner. How can I change the status bar text color to white like …

Read More