My application is using an NSURL like this:
var url = NSURL(string: "http://www.geonames.org/search.html?q=Aïn+Béïda+Algeria&country=")
When I tried to make a task for getting data from this NSURL like this:
let task = NSURLSession.sharedSession().dataTaskWithURL(url!, completionHandler: { (data: NSData!, response: NSURLResponse!, error: NSError!) -> Void in
if error == nil {
var urlContent = NSString(data: data, encoding: NSUTF8StringEncoding)
println("urlContent \(urlContent!)")
} else {
println("error mode")
}
but I got error when trying to got data from that address, although when I using safari go to link: "http://www.geonames.org/search.html?q=Aïn+Béïda+Algeria&country=" I can see the data. How can I fix that?
Swift 2
let original = "http://www.geonames.org/search.html?q=Aïn+Béïda+Algeria&country="
if let encodedString = original.stringByAddingPercentEncodingWithAllowedCharacters(
NSCharacterSet.URLFragmentAllowedCharacterSet()),
url = NSURL(string: encodedString)
{
print(url)
}
Encoded URL is now:
"http://www.geonames.org/search.html?q=A%C3%AFn+B%C3%A9%C3%AFda+Algeria&country="
and is compatible with NSURLSession
.
Swift 3
let original = "http://www.geonames.org/search.html?q=Aïn+Béïda+Algeria&country="
if let encoded = original.addingPercentEncoding(withAllowedCharacters: .urlFragmentAllowed),
let url = URL(string: encoded)
{
print(url)
}