Suppose I have this table [Table1]
Name Mark
------- ------
ABC 10
DEF 10
GHI 10
JKL 20
MNO 20
PQR 30
What should be my SQL statement to retrieve a record that looks like this: (group by [mark]). I have done the 1 and 2 columns but don't know how to accomplish the third column (concat the [name] with the same [mark])
mark count names
---- ----- -----------
10 3 ABC,DEF,GHI
20 2 JKL,MNO
30 1 PQR
I'm using Microsoft SQL. Please help. Thanks
If MS SQL 2005 or higher.
declare @t table([name] varchar(max), mark int)
insert @t values ('ABC', 10), ('DEF', 10), ('GHI', 10),
('JKL', 20), ('MNO', 20), ('PQR', 30)
select t.mark, COUNT(*) [count]
,STUFF((
select ',' + [name]
from @t t1
where t1.mark = t.mark
for xml path(''), type
).value('.', 'varchar(max)'), 1, 1, '') [values]
from @t t
group by t.mark
Output:
mark count values
----------- ----------- --------------
10 3 ABC,DEF,GHI
20 2 JKL,MNO
30 1 PQR