I have an entity that has an NON-ID field that must be set from a sequence. Currently, I fetch for the first value of the sequence, store it on the client's side, and compute from that value.
However, I'm looking for a "better" way of doing this. I have implemented a way to fetch the next sequence value:
public Long getNextKey()
{
Query query = session.createSQLQuery( "select nextval('mySequence')" );
Long key = ((BigInteger) query.uniqueResult()).longValue();
return key;
}
However, this way reduces the performance significantly (creation of ~5000 objects gets slowed down by a factor of 3 - from 5740ms to 13648ms ).
I have tried to add a "fake" entity:
@Entity
@SequenceGenerator(name = "sequence", sequenceName = "mySequence")
public class SequenceFetcher
{
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequence")
private long id;
public long getId() {
return id;
}
}
However this approach didn't work either (all the Ids returned were 0).
Can someone advise me how to fetch the next sequence value using Hibernate efficiently?
Edit: Upon investigation, I have discovered that calling Query query = session.createSQLQuery( "select nextval('mySequence')" );
is by far more inefficient than using the @GeneratedValue
- because of Hibernate somehow manages to reduce the number of fetches when accessing the sequence described by @GeneratedValue
.
For example, when I create 70,000 entities, (thus with 70,000 primary keys fetched from the same sequence), I get everything I need.
HOWEVER , Hibernate only issues 1404 select nextval ('local_key_sequence')
commands. NOTE: On the database side, the caching is set to 1.
If I try to fetch all the data manually, it will take me 70,000 selects, thus a huge difference in performance. Does anyone know the internal functioning of Hibernate, and how to reproduce it manually?
Here is what worked for me (specific to Oracle, but using scalar
seems to be the key)
Long getNext() {
Query query =
session.createSQLQuery("select MYSEQ.nextval as num from dual")
.addScalar("num", StandardBasicTypes.BIG_INTEGER);
return ((BigInteger) query.uniqueResult()).longValue();
}
Thanks to the posters here: springsource_forum