Oracle/SQL - Grouping items by action by day over time

Question

Hi all I have a 'widget' table that has the following columns: widget, action, timestamp_. What we want to do is pull all the widgets that were rejected more than once a day between certain dates. So here's an example table

widget      action      timestamp_
-------------------------------------------
type1       reject      2011-05-10 08:00:00
type1       reject      2011-05-10 09:00:00
type1       reject      2011-05-10 09:30:00
type2       reject      2011-05-11 09:30:00
type3       reject      2011-05-11 09:30:00
type1       reject      2011-05-11 09:30:00
type1       reject      2011-05-11 09:30:00
type2       reject      2011-05-12 10:30:00
type2       reject      2011-05-12 12:30:00
type3       reject      2011-05-12 12:30:00

So I anticipate wanting to see results in one of these two manners....

Between date x and y there were two widgets that were rejected multiple times in single days

This would see that type1 was rejected more than once in a day as was type2 thus the count is: 2

OR

Display each widget along with the date that it was rejected more than once and how many times. Example..

widget      date            count
---------------------------------
type1       2011-05-10      3
type1       2011-05-11      2
type2       2011-05-12      2

This would probably be the preferred output... but how?

Thanks in advance!

Answer 1

This would give your output:

SELECT Widget, to_char(timestamp_,'YYYY-MM-DD'), Count(Widget)
FROM Widget
WHERE timestamp_ BETWEEN to_date('YYYY-MM-DD HH24:MI:SS','%date1%') AND to_date('YYYY-MM-DD HH24:MI:SS','%date2%')
AND action LIKE 'reject'
GROUP BY Widget, to_char(timestamp_,'YYYY-MM-DD')
HAVING Count(Widget) > 1;

Of course, you'll want to replace the date variables.