What's a good way to check if two datetimes are on the same calendar day in TSQL?

Eric Z Beard picture Eric Z Beard · Aug 22, 2008 · Viewed 45.9k times · Source

Here is the issue I am having: I have a large query that needs to compare datetimes in the where clause to see if two dates are on the same day. My current solution, which sucks, is to send the datetimes into a UDF to convert them to midnight of the same day, and then check those dates for equality. When it comes to the query plan, this is a disaster, as are almost all UDFs in joins or where clauses. This is one of the only places in my application that I haven't been able to root out the functions and give the query optimizer something it can actually use to locate the best index.

In this case, merging the function code back into the query seems impractical.

I think I am missing something simple here.

Here's the function for reference.

if not exists (select * from dbo.sysobjects 
              where id = object_id(N'dbo.f_MakeDate') and               
              type in (N'FN', N'IF', N'TF', N'FS', N'FT'))
  exec('create function dbo.f_MakeDate() returns int as 
         begin declare @retval int return @retval end')
go

alter function dbo.f_MakeDate
(
    @Day datetime, 
    @Hour int, 
    @Minute int
)
returns datetime
as

/*

Creates a datetime using the year-month-day portion of @Day, and the 
@Hour and @Minute provided

*/

begin

declare @retval datetime
set @retval = cast(
    cast(datepart(m, @Day) as varchar(2)) + 
    '/' + 
    cast(datepart(d, @Day) as varchar(2)) + 
    '/' + 
    cast(datepart(yyyy, @Day) as varchar(4)) + 
    ' ' + 
    cast(@Hour as varchar(2)) + 
    ':' + 
    cast(@Minute as varchar(2)) as datetime)
return @retval
end

go

To complicate matters, I am joining on time zone tables to check the date against the local time, which could be different for every row:

where 
dbo.f_MakeDate(dateadd(hh, tz.Offset + 
    case when ds.LocalTimeZone is not null 
    then 1 else 0 end, t.TheDateINeedToCheck), 0, 0) = @activityDateMidnight

[Edit]

I'm incorporating @Todd's suggestion:

where datediff(day, dateadd(hh, tz.Offset + 
    case when ds.LocalTimeZone is not null 
    then 1 else 0 end, t.TheDateINeedToCheck), @ActivityDate) = 0

My misconception about how datediff works (the same day of year in consecutive years yields 366, not 0 as I expected) caused me to waste a lot of effort.

But the query plan didn't change. I think I need to go back to the drawing board with the whole thing.

Answer

Todd Tingen picture Todd Tingen · Aug 22, 2008

This is much more concise:

where 
  datediff(day, date1, date2) = 0