Simplest way to do a recursive self-join?

Chris picture Chris · Nov 18, 2009 · Viewed 104.1k times · Source

What is the simplest way of doing a recursive self-join in SQL Server? I have a table like this:

PersonID | Initials | ParentID
1          CJ         NULL
2          EB         1
3          MB         1
4          SW         2
5          YT         NULL
6          IS         5

And I want to be able to get the records only related to a hierarchy starting with a specific person. So If I requested CJ's hierarchy by PersonID=1 I would get:

PersonID | Initials | ParentID
1          CJ         NULL
2          EB         1
3          MB         1
4          SW         2

And for EB's I'd get:

PersonID | Initials | ParentID
2          EB         1
4          SW         2

I'm a bit stuck on this can can't think how to do it apart from a fixed-depth response based on a bunch of joins. This would do as it happens because we won't have many levels but I would like to do it properly.

Thanks! Chris.

Answer

Quassnoi picture Quassnoi · Nov 18, 2009
WITH    q AS 
        (
        SELECT  *
        FROM    mytable
        WHERE   ParentID IS NULL -- this condition defines the ultimate ancestors in your chain, change it as appropriate
        UNION ALL
        SELECT  m.*
        FROM    mytable m
        JOIN    q
        ON      m.parentID = q.PersonID
        )
SELECT  *
FROM    q

By adding the ordering condition, you can preserve the tree order:

WITH    q AS 
        (
        SELECT  m.*, CAST(ROW_NUMBER() OVER (ORDER BY m.PersonId) AS VARCHAR(MAX)) COLLATE Latin1_General_BIN AS bc
        FROM    mytable m
        WHERE   ParentID IS NULL
        UNION ALL
        SELECT  m.*,  q.bc + '.' + CAST(ROW_NUMBER() OVER (PARTITION BY m.ParentID ORDER BY m.PersonID) AS VARCHAR(MAX)) COLLATE Latin1_General_BIN
        FROM    mytable m
        JOIN    q
        ON      m.parentID = q.PersonID
        )
SELECT  *
FROM    q
ORDER BY
        bc

By changing the ORDER BY condition you can change the ordering of the siblings.