How can I create a unique index in Oracle but ignore nulls?
I am trying to create a unique constraint on two fields in a table. However, there is a high likelihood that one will be null. I only require that they be unique if both are not null (name will never be null).
create unique index "name_and_email" on user(name, email);
Ignore the semantics of the table and field names and whether that makes sense - I just made some up.
Is there a way to create a unique constraint on these fields that will enforce uniqueness for two not null values, but ignore if there are multiple entries where name is not null and email is null?
This question is for SQL Server, and I'm hoping that the answer is not the same: How do I create a unique constraint that also allows nulls?
Answer
We can do this with a function-based index. The following makes use of NVL2() which, as you know, returns one value if the expression is not null and a different value if it is null. You could use CASE() instead.
SQL> create table blah (name varchar2(10), email varchar2(20))
2 /
Table created.
SQL> create unique index blah_uidx on blah
2 (nvl2(email, name, null), nvl2(name, email, null))
3 /
Index created.
SQL> insert into blah values ('APC', null)
2 /
1 row created.
SQL> insert into blah values ('APC', null)
2 /
1 row created.
SQL> insert into blah values (null, '[email protected]')
2 /
1 row created.
SQL> insert into blah values (null, '[email protected]')
2 /
1 row created.
SQL> insert into blah values ('APC', '[email protected]')
2 /
1 row created.
SQL> insert into blah values ('APC', '[email protected]')
2 /
insert into blah values ('APC', '[email protected]')
*
ERROR at line 1:
ORA-00001: unique constraint (APC.BLAH_UIDX) violated
SQL>
Edit
Because in your scenario name will always be populated you will only need an index like this:
SQL> create unique index blah_uidx on blah
2 (nvl2(email, name, null), email)
3 /
Index created.
SQL>