Spring Resttemplate exception handling

Question

Below is the code snippet; basically, I am trying to propagate the exception when the error code is anything other than 200.

ResponseEntity<Object> response = restTemplate.exchange(url.toString().replace("{version}", version),
                    HttpMethod.POST, entity, Object.class);
            if(response.getStatusCode().value()!= 200){
                logger.debug("Encountered Error while Calling API");
                throw new ApplicationException();
            }

However in the case of a 500 response from the server I am getting the exception

org.springframework.web.client.HttpServerErrorException: 500 Internal Server Error
    at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:94) ~[spring-web-4.2.3.RELEASE.jar:4.2.3.RELEASE]

Do I really need to wrap the rest template exchange method in try? What would then be the purpose of codes?

Answer 1

You want to create a class that implements ResponseErrorHandler and then use an instance of it to set the error handling of your rest template:

public class MyErrorHandler implements ResponseErrorHandler {
  @Override
  public void handleError(ClientHttpResponse response) throws IOException {
    // your error handling here
  }

  @Override
  public boolean hasError(ClientHttpResponse response) throws IOException {
     ...
  }
}

[...]

public static void main(String args[]) {
  RestTemplate restTemplate = new RestTemplate();
  restTemplate.setErrorHandler(new MyErrorHandler());
}

Also, Spring has the class DefaultResponseErrorHandler, which you can extend instead of implementing the interface, in case you only want to override the handleError method.

public class MyErrorHandler extends DefaultResponseErrorHandler {
  @Override
  public void handleError(ClientHttpResponse response) throws IOException {
    // your error handling here
  }
}

Take a look at its source code to have an idea of how Spring handles HTTP errors.