How can I set the DataContext on my Grid in XAML, instead of in the constructor?
Here is how I do it in the constructor (LayoutRoot is the XAML Grid defined in the XAML):
this.LayoutRoot.DataContext = this.HPVM;
I would prefer to do it right in the XAML, but I do not know how to reference the HPVM object in XAML. HPVM is a public property on the USerControl class.
It works fine as listed above, but again, I just want to know how to properties of the UserControl class in XAML, rather than always having to do it in code.
Here is all the relevant code:
<UserControl x:Class="SilverlightApplication1.SLHolePattern" x:Name="HolePatternsControl"
xmlns="http://schemas.microsoft.com/client/2007"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:sys="clr-namespace:System;assembly=mscorlib"
xmlns:controls="clr-namespace:Microsoft.Windows.Controls;assembly=Microsoft.Windows.Controls"
xmlns:local="clr-namespace:SilverlightApplication1"
xmlns:GeoPatterns="clr-namespace:GeoPatterns"
Height="700">
<UserControl.Resources>
...
And here is my constructor where the DataContext is currently set:
namespace SilverlightApplication1
{
public partial class SLHolePattern : UserControl, INotifyPropertyChanged
{
public HolePatternsViewModel HPVM;
public SLHolePattern()
{
InitializeComponent();
this.HPVM=new HolePatternsViewModel();
this.LayoutRoot.DataContext = this.HPVM;
...more code here
}
It all works fine, but I just want to learn how to set the DataContext in XAML, not in code.
The answer Chris gave works just fine. I have tested and it worked for me. You can instantiate your class in XAML (within the UserControl.Resources) and then bind the datacontext to a static resource.
Follow code:
<UserControl ...>
<UserControl.Resources>
<myNS:MyClass x:Name="TheContext" x:Key="TheContext"></myNS:MyClass>
</UserControl.Resources>
<Grid x:Name="LayoutRoot" Background="White" DataContext="{StaticResource TheContext}" >
<TextBlock Text="{Binding Path=Field1}">
</TextBlock>
</Grid>
</UserControl>