Find all zips, and unzip in place - Unix

ThePerson picture ThePerson · Feb 11, 2013 · Viewed 29.8k times · Source

I have been trying for some time and believe I am fairly close to this, but I am fairly new to Unix so have been finding this difficult.

I have a folder, containing many folders, some of which have zip files in them, some which don't. I am trying to unzip all of the zip files in any sub directories in place.

For example I have:

files/A/something.java

files/B/somezipfile.zip

files/C/someotherfile.zip

files/D/AnotherZipFile.zip

I would like to unzip them (assuming the zips contain just .java files), to have a result like: files/A/something.java

files/B/javafile.java

files/C/someotherfilefromzip.java

files/D/Anotherfile.java

I don't mind if the ZIP files remain or are deleted after unzipping, either is fine.

What I have tried so far.

1) I expected I could use piping, which I am new to, like this:

find . -name *.zip | unzip

This doesn't work.

2) I spent some time searching, the closest I got using a solution online is:

find . -name '*.zip' -exec unzip '{}' ';'

This unzips, but unzips them into the current working directory, I wanted them to unzip in place. I also don't understand this command which I would like to as I am trying to learn.

Any help is much appreciated.

Thanks,

Answer

Mikhail Vladimirov picture Mikhail Vladimirov · Feb 11, 2013
find . -name '*.zip' -exec sh -c 'unzip -d `dirname {}` {}' ';'

This command looks in current directory and in its subdirectories recursively for files with names matching *.zip pattern. For file found it executes command sh with two parameters:

-c

and

unzip -d `dirname <filename>` <filename>

Where <filename> is name of file that was found. Command sh is Unix shell interpreter. Option -c tells shell that next argument should be interpreted as shell script. So shell interprets the following script:

unzip -d `dirname <filename>` <filename>

Before running unzip shell expands the command, by doing various substitutions. In this particular example it substitutes

`dirname <filename>`

with output of command dirname <filename> which actually outputs directory name where file is placed. So, if file name is ./a/b/c/d.zip, shell will run unzip like this:

unzip -d ./a/b/c ./a/b/c/d.zip

In case you ZIP file names or directory names have spaces, use this:

find . -name '*.zip' -exec sh -c 'unzip -d "`dirname \"{}\"`" "{}"' ';'