Get email ID of user in SPServices

Mujtaba Hassan picture Mujtaba Hassan · Nov 14, 2012 · Viewed 7.9k times · Source

I am using SPServices (GetListItems method) to fetch some information from a sharepoint list. The list contains a "People or Group" type field which returns a numeric id and name(Display name) of the user separated by semi-colon like this "43#;John Doe". I need the email addresses of all the users in this field (in all the rows returned). Can anyone help? Thanks in advance.

Answer

Mujtaba Hassan picture Mujtaba Hassan · Nov 20, 2012

Paul you rock :)

From Paul's last comment I got the required thing. Its perfect. :)

Only thing you need is to add the following to the call

CAMLQueryOptions: "<QueryOptions><ExpandUserField>True</ExpandUserField></QueryOptions>",

SO my example call becomes this

$().SPServices({ operation: "GetListItems", async: false, listName: "Assignees", webURL: "https://col.wow.telenor.com/sites/go/",
            CAMLViewFields: "<ViewFields Properties='True'/>",
            CAMLQuery: "",
            CAMLQueryOptions: "<QueryOptions><ExpandUserField>True</ExpandUserField></QueryOptions>",
            completefunc: function (xData,Status) {

                $(xData.responseXML).SPFilterNode("z:row").each(function () {

                    try {
                    //ows_Name1 is a field of type "People or Group" the after adding CAMLQueryOptions this field returns all the fields
                    // propeties of user i.e. Displayname,ID,email id, domain login, sip ID etc all separate by #
                        var title = $(this).attr("ows_Name1"); 
                    // Splitting the resultant string with # give you string array of all the properties. In my case email ID is at 
                    // index 3.
                        var userEmail = userText.split('#')[3];
                    // Below line is added to remove the trailing "," from email id
                        userEmail = userEmail.substring(0,userEmail.indexOf(','));

                    }
                    catch (e) {
                        alert('Exception: ' + e.message);
                    }
                });
            }
        });

Sorry Paul I have to unmark you answer and make this one answer :)