(define (subtract-1 n)
(string-append "Number is: " (number->string n))
(cond
[(= n 0) "All done!"]
[else (subtract-1(- n 1))]))
I keep getting the error: define: expected only one expression for the function body, but found 1 extra part. I'm not understanding why I'm getting this.
NOTE TO SELF: When using DrRacket, Setting the language to BSL may make Racket commands error at compile time.
The language you're using (BSL) only allows a single expression inside the body of a procedure, if there's more than one expression, you need to pack them inside a begin
.
Also notice that the string-append
line is doing nothing, you should print it or accumulate it. Here's a possible solution with my recommendations in place:
(define (subtract-1 n)
(begin
(display (string-append "Number is: " (number->string n) "\n"))
(cond
[(= n 0) "All done!"]
[else (subtract-1 (- n 1))])))
Even better, use the printf
procedure for simplicity's sake:
(define (subtract-1 n)
(begin
(printf "~a ~s~n" "Number is:" n)
(cond
[(= n 0) "All done!"]
[else (subtract-1 (- n 1))])))
Either way a sample execution looks like this:
(subtract-1 3)
=> Number is: 3
=> Number is: 2
=> Number is: 1
=> Number is: 0
=> "All done!"