I am trying to convert a column which contains Array[String] to String, but I consistently get this error
org.apache.spark.SparkException: Job aborted due to stage failure: Task 0 in stage 78.0 failed 4 times, most recent failure: Lost task 0.3 in stage 78.0 (TID 1691, ip-******): java.lang.ClassCastException: scala.collection.mutable.WrappedArray$ofRef cannot be cast to [Ljava.lang.String;
Here's the piece of code
val mkString = udf((arrayCol:Array[String])=>arrayCol.mkString(","))
val dfWithString=df.select($"arrayCol").withColumn("arrayString",
mkString($"arrayCol"))
WrappedArray
is not an Array
(which is plain old Java Array
not a natve Scala collection). You can either change signature to:
import scala.collection.mutable.WrappedArray
(arrayCol: WrappedArray[String]) => arrayCol.mkString(",")
or use one of the supertypes like Seq
:
(arrayCol: Seq[String]) => arrayCol.mkString(",")
In the recent Spark versions you can use concat_ws
instead:
import org.apache.spark.sql.functions.concat_ws
df.select(concat_ws(",", $"arrayCol"))