How do I decode a URL and get the query string as a HashMap?

Question

I have a URL like this:

http%3A%2F%2Fexample.com%3Fa%3D1%26b%3D2%26c%3D3

I parsed it with hyper::Url::parse and fetch the query string:

let parsed_url = hyper::Url::parse(&u).unwrap();
let query_string = parsed_url.query();

But it gives me the query as a string. I want to get the query string as HashMap. something like this:

// some code to convert query string to HashMap
hash_query.get(&"a"); // eq to 1
hash_query.get(&"b"); // eq to 2

Answer 1

There are a few steps involved:

• The .query_pairs() method will give you an iterator over pairs of Cow<str>.

• Calling .into_owned() on that will give you an iterator over String pairs instead.

• This is an iterator of (String, String), which is exactly the right shape to .collect() into a HashMap<String, String>.

Putting it together:

let parsed_url = Url::parse("http://example.com/?a=1&b=2&c=3").unwrap();
let hash_query: HashMap<_, _> = parsed_url.query_pairs().into_owned().collect();
assert_eq!(hash_query.get("a"), "1");

Note that you need a type annotation on the hash_query—since .collect() is overloaded, you have to tell the compiler which collection type you want.