Ruby: OptionParser: String Arg & Hash Assignment

Question

Using OptionParser for string argument input and hash assignment. What is the best way to read-in multiple variables for a single argument? How do I then assign those to a hash to reference? Here is what I have so far:

large_skus = Hash.new
small_skus = Hash.new

OptionParser.new do |opts|

opts.on("-b", "--brands bName1,bName2,bNameN", String, "Check specific brands by name") do |b|
 options[:brands] = b.split(",")
end

opts.on("-l", "--large lSku1,lSku2,lSkuN", String, "Large SKUs - List CSVs") do |l|
 options[:large_skus] = l.split(",")
 ##For each sku given
 brandName = options[:brands]
 large_skus[brandName] = l[$sku].to_i
 ##
end

opts.on("-s", "--small sSku1,sSku2,sSkuN", String, "Small SKUs - List CSVs") do |s|
 options[:small_skus] = s.split(",")
 ##For each sku given
 brandName = options[:brands]
 small_skus[brandName] = s[$sku].to_i
 ##
end

end.parse!(ARGV)

Answer 1

Given an input of:

 ruby test.rb --brands bName1,bName2,bNameN --large lSku1,lSku2,lSkuN --small wQueue1,wQueue2,wQueueN

This code

#!/usr/bin/env ruby

require 'ap'
require 'optparse'

options = {}
OptionParser.new do |opts|

  opts.on("-b", "--brands bName1,bName2,bNameN", Array, "Check specific brands by name") do |b|
    options[:brands] = b
  end

  opts.on("-l", "--large lSku1,lSku2,lSkuN", Array, "Large SKUs - List CSVs") do |l|
    options[:large_skus] = l
  end

  opts.on("-s", "--small wQueue1,wQueue2,wQueueN", Array, "Small SKUs - List CSVs") do |s|
    options[:small_skus] = s
  end

end.parse!(ARGV)

ap options

Produces this output:

{
        :brands => [
        [0] "bName1",
        [1] "bName2",
        [2] "bNameN"
    ],
    :large_skus => [
        [0] "lSku1",
        [1] "lSku2",
        [2] "lSkuN"
    ],
    :small_skus => [
        [0] "wQueue1",
        [1] "wQueue2",
        [2] "wQueueN"
    ]
}

Notice that instead of using types of String for each option, I'm using Array. That lets OptionParser do the heavy lifting of parsing the elements into an array. From that point it's up to you what you do with the array elements.